apa hasil dari persamaan eksponen berikut
[tex]2 {}^{3x + 8} = 5 {}^{3x + 8} [/tex]
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[tex]2 {}^{3x + 8} = 5 {}^{3x + 8} [/tex]
[tex] \boxed{\begin{aligned}\sf {2}^{3x + 8} &=\sf {5}^{3x + 8}\\ \sf {\left(\dfrac{2}{5} \right)}^{3x + 8}&=\sf 1\\ \sf {\left(\dfrac{2}{5} \right)}^{3x + 8}&= \sf {\left(\dfrac{2}{5} \right)}^{0}\\ \sf 3x + 8&=\sf 0\\ \sf 3x&=\sf0 - 8\\ \sf 3x&=\sf - 8\\ \sf x&=\sf - \frac{8}{3} = - 2 \frac{2}{3} \end{aligned}}[/tex]
Penjelasan dengan langkah-langkah:
Eksponen
.
Rumusnya;
[tex] {a}^{g(x)} = {b}^{g(x)} \\ maka \\ g(x) = 0[/tex]
Sehingga;
[tex] {2}^{3x + 8} = {5}^{3x + 8} \\ 3x + 8 = 0 \\ 3x = - 8 \\ x = - \frac{8}{3} \\ or \\ x = - 2 \frac{2}{3} [/tex]
Semoga Membantu
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